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The third ionisation energy of Al((g)) i...

The third ionisation energy of `Al_((g))` is equal to :

A

`IE_(1)" of "Al^(2+)(g)`

B

`IE_(2)" of "Al^(+)(g)`

C

`IE_(2)" of "Al^(2+)(g)`

D

`IE_(1)" of "Al^(+)(g)`

Text Solution

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The correct Answer is:
A, B

`Al_((g))overset(l.E_(1)" of "Al)rarrAl_((g))^(+)underset(l.E_(1)" of "Al_((g))^(2+))overset(l.E_(2)" of "Al_((g)))rarrAl_((g))^(2+)undersetunderset(l.E_(2)" of "Al_((g))^(+))(l.E_(1)" of "Al_((g))^(2+))overset(l.E_(3)" of "Al_((g)))rarrAl^(3+)`
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