A ball is projected horizontally from the top of tower at `12 m//s` as shown in figure. Wind is blowing as indicated (Horizontally) which causes acceleration `6 m//s^(2)` horizontally. Magnitude of displacent of ball when it strikes back the tower `(g = 10 m//s^(2))`

Options

A. 20m
B. 60m
C. 80m
D. 40m

Answer

C

Explanation

If ball strikes the tower back
implies Net displacent along x-direction = 0
`{:("y- direction",|,"So.x - direction",),(u_(y)implies0,u_(x)=+12,,),(a_(y)=-10,a_(x)=-6,,),(t implies 4 " sec",s_(x)=0,,),(s_(y)implies-(1)/(2)xx10xx(4)^(2),0=+12t-(6)/(2)xxt^(2),,),(implies-80,timplies4" sec",,):}`