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Mole fraction of liquid A (M = 20) prese...

Mole fraction of liquid A (M = 20) present with liquid B(M = 25) in a solution of A (l) and B (l) is 0.6, then weight of solution per 50 g of liquid B is :

A

55g

B

110g

C

220g

D

150g

Text Solution

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The correct Answer is:
B
`n_(A)=6 " mas of "A = 6xx20 =120 g`
`n_(B)=4 " mas of "B = 4xx25 =100 g`
`100 g " of "B = 220 g ` of solution
50 g of B = 110 g of solution
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