A block of mass 1 kg is stationary with respect to a conveyor belt that is accelerating with `1 m//s ^(2)` upwards at an angle of `30^(@)` as shown in figure. Contact force between the block & belt is 3.5x. What is the value of x ?

Answer

1 kg

Explanation

For constant velocity
`T = mg " " ……(1)`
`T = gsin theta + mg cos theta" "……..(2)`
From (1) & (2)
`mg = g sin theta + mg cos theta`
`m = sin theta + mcos theta`
`= (3)/(5)+(1)/(2)xx(4)/(5)=1kg`