What should be minimum value of F so that 2 kg slides on ground but 1kg does not slide on it? `[g = 10m/sec^(2)]`

Answer

2

Explanation

`(m_(1)-2m_(2)//2m_(2))g`
Initially 2T = `m_(1)g`
After string is cut
`T - m_(2) g =m_(2)a`
`(m_(1)g)/(2)-m_(2)g=m_(2)a`
`g. ((m_(1)-2m_(2)))/(2m_(2))=a`
`m_(1)=6" and "m_(2) = 2.5`
then `a = 2ms^(-2)`