10 ml of a mixture of `C_(2)H_(2)` and CO gas was exploded with 15ml of oxygen. The gases after the reaction had a volume of 17 ml at 298 K calculate volume of oxygen remained after treatment the resulting gas mixture with KOH.

Answer

6

Explanation

mol of `SO_(2) (M) = (12)/(64)g" " , " mol of "SO_(3)(N) = (10)/(80)g" "because(4M)/(N)=((4xx12)/(64))/((10)/(80))=6`