A particle moves in a straight line with an acceleration a `ms^(-2)` at time 't' seconds where a `=-(1)/(t^(2))`. When t = 1 the particle has a velocity of `3ms^(-1)` then the velocity when t = 4 is `(v)/(4)`. Find the value of v.

Answer

d=5 m

Explanation

`v^(2) = 2as`
`(70xx(5)/(18))^(2)=2xxaxx13d`
`a=((35xx5)/(9))^(2)(1)/(26d)`
`ma = mu mg`
`((35xx5)/(9))^(2)(1)/(26d)=0.3 xx 98`
`d=((35xx5)/(9))^(2)26xx3`
`d~~ 4.94`