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In 100 ml of 5 M H(2)SO(4) (aq) solution...

In 100 ml of 5 M `H_(2)SO_(4)` (aq) solution 'x' ml of `H_(2)O` (l) is added. If 20 ml of this diluted `H_(2)SO_(4)` solution is completely neutralised by 100 ml of `0.4 M` NaOH solution.
What is the value of `(x)/(80)`?

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Verified by Experts

The correct Answer is:
3
`chi_("pauling")=(chi_("Mulliken"))/(2.8)=(l.E+E.A)/(2xx2.8)=(13.0+3.8)/(2xx2.8)=3.0`
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