Home
Class 12
PHYSICS
A stone of mass M is tied at the end of ...

A stone of mass M is tied at the end of a string, is moving in a circle of radius R, with a constant angular velocity `omega`. The total work done on the stone, in any half circle, is:

A

`piMR^(2)omega^(2)`

B

`2MR^(2)omega^(2)`

C

`MR^(2)omega^(2)`

D

0

Text Solution

Verified by Experts

The correct Answer is:
B
`W_("gravity")=DeltaU_("spring")`
`mg sintheta(d+0.25) = (1)/(2)K(0.25)^(2)`
which gives d = 37.5 cm
Promotional Banner

Topper's Solved these Questions

  • REVIEW TEST

    VIBRANT|Exercise PART - II : PHYSICS|262 Videos

  • TEST PAPERS

    VIBRANT|Exercise PART - II : PHYSICS|56 Videos

Similar Questions

Explore conceptually related problems

A stone of mass m is tied to a strin and is moved in a vertical circle of radius r making n revolution per minute. The total tension in the string when the stone is its lowest point is.

A small steel shphere tied at the end of a string is whirled in a horizontal circle with uniform angular velocity omega the string is suddently pulled so that the radius of the circle is halved .If omega_(2) is the angular velocity then

Stone of mass 1 kg tied to the end of a string of length 1m , is whirled in horizontal circle with a uniform angular velocity 2 rad s^(-1) . The tension of the string is (in newton)

Three point masses each of mass m rotate in a circle of radius r with constant angular velocity omega due to their mutual gravitational attraction. If at any instant, the masses are on the vertices of an equilateral triangle of side a , then the value of omega is

A stone of of mass 0 .25 kg tied to the end of a string is whirled round in a circle of radius 1.5 m with a speed of 40 rev//min in a horizontal plane What is the tension in the string ? What is the maximum speed with which the stone can be whirled around If the string can withstand a maximum tension of 200 N ?

If a particle moves in a circle of radius r with constant speed under centripetal force F, then the work done in completing full circle will be ,

A particle moves along a circle of radius R with a constant angular speed omega . Its displacement (only magnitude) in time t will be

A particle moves along a circle of radius R with a constant angular speed omega . Its displacement (only magnitude) in time t will be

A body of mass m is movinng in a circlee off radius r with a constant speed v. the work done by the centripetal force in moving the body over half the circumference of the circle is

A stone tied at the end of string is whirled in a circle. If the string break, the stone flies away tangentially . Why ?

VIBRANT-REVIEW TEST-PART - II : PHYSICS
  1. A stone of mass M is tied at the end of a string, is moving in a circl...

    Text Solution

    |

  2. In (x-y) plane motion of particle it's (x-y) coordinate depends on tim...

    Text Solution

    |

  3. Three forces of magnitude 10N are acting on a block of mass 2 kg at 12...

    Text Solution

    |

  4. Find int(0)^(1)picos((pi)/(2)t)dt=?

    Text Solution

    |

  5. During displacement of a body two forces are acting on it simultaneous...

    Text Solution

    |

  6. Resultant of two forces when angle between them is 60^(@) is 6 Newton ...

    Text Solution

    |

  7. Force vec(F)=(4sqrt(2hat(i))+3sqrt(2)hat(j)) acting on a body so that ...

    Text Solution

    |

  8. Two forces 10 N and 15 N are acting on a body then which cannot be the...

    Text Solution

    |

  9. If acceleration of particle changing with time is a = (4t-2) m//s^(2) ...

    Text Solution

    |

  10. Young modulus of steel is 3 xx 10^(11) N//m^(2). When expressed in C.G...

    Text Solution

    |

  11. If momentum P, area A and time T are selected as fundamental quantitie...

    Text Solution

    |

  12. Two forces are acting on body vec(F)(1)=-(50-t^(2))hat(j) Newton and v...

    Text Solution

    |

  13. In the given velocity v//s position graph find acceleration at x = 2m

    Text Solution

    |

  14. Select correct statements

    Text Solution

    |

  15. If x = (4t^(2)+2) any y = 2t, then find ((dx)/(dy)) at t = 2 sec. (x i...

    Text Solution

    |

  16. Which of the following cannot be the group of fundamental quantities. ...

    Text Solution

    |

  17. Statement-1 : Using dimensional analysis we can drive only those formu...

    Text Solution

    |

  18. If side length of cube changing at 0.1mm//sec. Then what will be rate ...

    Text Solution

    |

  19. During one dimensional motion on x-axis Velocity time graph for partic...

    Text Solution

    |

  20. During one dimensional motion on x-axis Velocity time graph for partic...

    Text Solution

    |

  21. During one dimensional motion on x-axis Velocity time graph for partic...

    Text Solution

    |