The value of four quantum number for the last electron of atom of element x are n = 7, l = 1 and `m = +1` and `s=+1//2" or "-1//2` and magnetic moment of element x is zero.
The incorrect statement regarding element x is

Options

A. Element x belongs to `16^(th)` group.
B. Atomic number of x is 118
C. Element x belongs to `18^(th)` group.
D. Eight electrons are present in valence shell.

Answer

C

Explanation

x is `As rarr[Ar] 3d^(10)4s^(2)4p^(3)`
`2|s|+1=4" "|s|=3//2`
So, unpaired electron in electronic element x is 3.