`C_(2)H_(4)(g)+Br_(2)(g)iff C_(2)H_(4)Br_(2)(g)`
The above reaction establishes equilibrium after some time at a fixed temperature if 4 moles of `C_(2)H_(4)` and 2.5 mole of `Br^(2)` initially taken in closed vessel then value of `K_(c )` obtained is `x xx10^(-y)`. Find x - y ?

Answer

4

Explanation

`4HNO_(3)(g)iff4NO_(2)(g)+2H_(2)O(g)+O_(2)(g)`
`P_(eq)=30=P_(HNO_(3))+P_(NO_(2))+P_(H_(2)O)+P_(O_(2))`
`28 = P_(NO_(2))+P_(H_(2)O)+P_(O_(2))," "P_(NO_(2))=(4)/(7)xx28=16"atm " ,P_(NO_(2))=8"atm",P_(O_(2))=4"atm"`
`therefore" "K_(p)=(P_(NO_(2))^(4)xxP_(H_(2)O)^(2)xxP_(O_(2)))/(P_(HNO_(3))^(4))=(16^(4)xx8^(2)xx4)/(2^(4))`
`K_(c )=K_(p)(RT)^(-Deltan_(g))=(16^(4)xx8^(2)xx4)/(2^(4))xx(0.08xx400)^(-3) = 32`
`therefore " "(K_(c ))/(8)=4`