A particle starts moving in a straight line under an acceleration varying linearly with time. Its velocity time graph is as shown in figure. Its velocity is maximum at t = 3 sec. The time (in sec) when the particle stops is `(tan 37^(@) = 3//4)`

Answer

7

Explanation

a = C - Kt
At t = 0, `a = tan 37^(@)`
`(3)/(4) = C`
at `t = 3, a = 0`
`0=(3)/(4)-Kxx3 implies K=(1)/(4)`
`a=(3)/(4)-(1)/(4)t`
Particle stops, when a = `-tan45^(@)=-1`
`-1=(3)/(4)-(1)/(4)`
`(t)/(4)=(7)/(4)implies t=7sec`