Two projectiles are projected with velocity `v_(A), v_(B)` at angles `theta_(A)` (from horizontal) and `theta_(B)` (from vertical) as shown in the figure below, such that `v_(A) gt v_(B)` but having same horizontal component of velocity. Which of the following is correct ?

Options

A. `T_(A) gt T_(B)`
B. `H_(A) gt H_(B)`
C. `R_(A) gt R_(B)`
D. `R_(B) gt R_(A)`

Answer

A, B, C

Explanation

`v_(AX)=v_(BX)`
`v_(Ay)^(2)+v_(Bx)^(2)gtv_(By)^(2)+v_(Bx)^(2)`
`thereforev_(Ay)gtv_(By)`
`R=(2v_(x)v_(y))/(g)" "thereforeR_(A) gtR_(B)`
`H=(2v_(y)^(2))/(g)" "thereforeH_(A)gtH_(B)`
`T=(2v_(y))/(g)" "thereforeT_(A)gtT_(B)`