Motion of a particle can be split into two parts in the first part it's average speed is `V_(1)` and in the second it's average speed is `V_(2)`. For the whole motion the average speed is geometric mean of `V_(1)` and `V_(2) i.e. sqrt(V_(1)V_(2))` Determine the ratio of distance covered in the two parts of the motion.

Options

A. `sqrt((V_(1))/(V_(2)))`
B. `(V_(1))/(V_(2))`
C. `sqrt((V_(2))/(V_(1)))`
D. `(V_(1)^(2))/(V_(2)^(2))`

Answer

A

Explanation

Lets & spare two distance. So:
`[(S_(1))/(V_(1))+(S_(2))/(V_(2))]=(S_(1)+S_(2))/(sqrt(V_(1)V_(2)))`
`(S_(1))/(S_(2))=sqrt((V_(1))/(V_(2)))`