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A particle is released from rest from a tower of height 3h. The ratio of the intervals of time to cover three equal height h is.

A

`t_(1) : t_(2) : t_(3) = 3 : 2 : 1`

B

`t_(1) : t_(2) : t_(3) = 1 : (sqrt(2)-1) : (sqrt(3) - 2)`

C

`t_(1) : t_(2) : t_(3) = 1 : sqrt(2) : sqrt(3)`

D

`t_(1) : t_(2) : t_(3) = 1 : (sqrt(2) - 1) : (sqrt(3) - sqrt(2))`

Text Solution

Verified by Experts

The correct Answer is:
D

`t_(1)=sqrt((2h)/(g))`
`t_(2)=sqrt((4h)/(g))-sqrt((2h)/(g))`
`t_(3)=sqrt((6h)/(g))-sqrt((4h)/(g))`
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