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The block of mass M moving on the frict...

The block of mass `M` moving on the frictionless horizontal surface collides with the spring constant `k` and compresses it by length `L` . The maximum momention of the block after collision is

A

Zero

B

`(ML^(2))/(K)`

C

`Lsqrt(MK)`

D

`(KL^(2))/(2M)`

Text Solution

Verified by Experts

The correct Answer is:
C
`(1)/(2)MV^(2)=(KL)/(2)=(P^(2))/(2M)`
`P=Lsqrt(KM)`
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