A small block slides without friction down an iclined plane starting form rest. Let `S_(n)` be the distance traveled from time `t = n - 1` to `t = n`. Then `(S_(n))/(S_(n + 1))` is:

Options

A. `((2n-1))/(2n)`
B. `((2n+1))/((2n-1))`
C. `((2n-1)/(2n+1))`
D. `((2n)/(2n+1))`

Answer

C

Explanation

Distance travelled in `t^(th)` second is
`S_(t)=u+(a)/(2)(2t-1)`
`u = 0`
`S_(n)=(a)/(2)(2n-1)`
`S_((n)/(n+1))=(a)/(2)[2n+1]`
`(S_(n))/(S_(n+1))=((2n-1))/((2n+1))`