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For the dissociation of NH(3)(g) as 2NH(...

For the dissociation of `NH_(3)(g)` as `2NH_(3)(g)iffN_(2)(g)+3H_(2)(g)`, the variation of `(1 + alpha)` against `((D)/(d))` is represented as : (Given : D = initial vapour density of `PCl_(5)`, d = Vapour density of mixture at equilibriu,):

A

B

C

D

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Verified by Experts

The correct Answer is:
A

`2NH_(3)(g) iff N_(2) (g) + 3H_(2)(g)`
`alpha=(D-d)/((n-1)d) " "because n = 2`
`therefore 1 + alpha = ((D)/(d))`
`therefore y = x`
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