A box is failing freely. Inside the box, a particle is projected with some velocity v with respect to the box at an angle `theta` as shown in the figure.

Options

A. The path of the particle with respect to an observer sitting in the box will be a straight line.
B. The acceleration of particle with respect to the box is zero.
C. The path of the particle with respect to an observer sitting in the box will be a parabola
D. The acceleration of particle with respect to ground is g downward

Answer

A, B, C

Explanation

Loss in KE = `(1)/(2) (m_(1)m_(2))/(m_(1)+m_(2))(V_("rel"))^(2)(1-e^(2))`