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A long horizontal plank of mass m is lyi...

A long horizontal plank of mass `m` is lying on a smooth horizontal surface. A sphere of same mass `m` and radius `r` is spinned about its own axis with angular velocity we and gently placed on the plank. The coefficient of friction between the plank and the sphere is `mu`. After some time the pure rolling of the sphere on the plank will start. Answer the following questions.

Find the displacement of the plank till the sphere starts pure rolling.

A

`(omega_(0)^(2)r^(2))/(81mug)`

B

`(2)/(27)(omega_(0)^(2)r^(2))/(mug)`

C

`(4)/(81)(omega_(0)^(2)r^(2))/(mug)`

D

`(2)/(81)(omega_(0)^(2)r^(2))/(81mug)`

Text Solution

Verified by Experts

The correct Answer is:
D

`V_(1)=(2)/(sqrt(5))sqrt(5gR)=2sqrt(gR)`
`V_(2)^(2)=V_(1)^(2)-2g(R+Rsintheta)=2gR-2gRsintheta`
N + `mgsintheta=(mV_(2)^(2))/(R )`
Putting N = 0 implies `mgsintheta = m2g(1-sintheta)`
` implies theta=sin^(-1)((2)/(3))`
`V^(2)=V_(1)^(2)-2gRimpliesV^(2)=4gR-2gR`
`V=sqrt(2gR)`
`a_(c )=(V^(2))/(R )=2gimpliesa_(t)=g`
`tan alpha=(a_(t))/(a_(c ))impliesalpha=tan^(-1)((1)/(2))`
Maximum contact force is at A.
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