Velocity of a particle moving in a straight line is `v=sqrt(9+4s)`. Here v is in m/s and 's' displacement in meter. Mass of the particle is 2kg. The time in seconds at which average power is `((3)/(4))^(th)` of the instantaneous power is :

Options

A. 0.92
B. 0.67
C. 1.5
D. `3.0`

Answer

B

Explanation

Maximum energy stored in spring `=(1)/(2)mu V_("ret")^(2)=(1)/(2)((mm)/(m+m))(V_(0)^(2))=(1)/(4)mV_(0)^(2)`