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A small body with relative density d(1) ...

A small body with relative density `d_(1)` falls in air from a height 'h' on to the surface of a liquid of relative density `d_(2)` where `d_(2)gt d_(1)`. The time elapsed after entering the liquid to the instant when it comes to instantaneous rest inside liquid

A

`sqrt((2h)/(g))(d_(2))/(d_(1))`

B

`sqrt((2h)/(g))((d_(1))/(d_(2)-d_(1)))`

C

`sqrt((2h)/(g))(d_(1))/(d_(2))`

D

`sqrt((2h)/(g))((d_(2)-d_(1)))/(d_(1))`

Text Solution

Verified by Experts

The correct Answer is:
D

`(dQ)/(dt)=-KA (dT)/(dx)=-alphaTA (dT)/(dx)`
`(dQ)/(dt)=-alphaAT(dT)/(dx)impliesi=-alphaAT(dT)/(dx)implies iintdx =- alphaAunderset(T_(1))overset(T_(2))intTdT`
`implies i(l)=alphaA((T_(1)^(2)-T_(1)^(2)))/(2)implies i=(alphaA)/(2l)(T_(1)^(2)-T_(2)^(2))`
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