The dissociation equilibrium of a gas `AB_(2)` can be represented as, `2AB_(2)(g)iff2AB(g)+B_(2)(g)`. The degree of dissociation is x and is small compared to 1. The expression relating the degree of dissociation (x) with equilibrium constant `k_(p)` and total pressure P is :

Options

A. `(k_(p))/(P)`
B. `(2k_(p))/(P)`
C. `((2k_(p))/(P))^(1//3)`
D. `((2k_(p))/(P))^(1//2)`

Answer

D

Explanation

`BeCl_(2) lt AlCl_(3) lt SiCl_(4)`
`C Cl_(4)ltPCl_(5)ltPF_(5)`
`Na^(+) lt Mg^(2+) lt Al^(3+)`