Prove that `log2+16log16/15+12log25/24+7log81/80=1`

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Prove that log2+16log (16/15)+12log(25/24)+7log(81/80)=1

prove that log2 + 16 log(16/15) + 12 log(25/24) + 7 log(81/80) = 1

Prove that log 2 + 16 "log"16/15 + 12 "log" 25/24 + 7 "log" 81/80 = 1

prove that log2+16log((16)/(15))+12log((25)/(24))+7log((81)/(80))=1

Prove that log_2 log_2 log_2 16=1

Prove that log_2log_2log_(2) 16 =1

The value of 7log(16/15)+5log(25/24)+3log(81/80)=

Evaluate : 7"log"16/15+ 5"log"25/24+3"log"81/80

Prove that "log" 2 + 16 "log" (16)/(15) + 12 "log " (25)/(24) + 7 "log"(81)/(80) = 1 .

Simplify : (ii) 23 log 16/15 + 17log 25/24 + 10log 81/80