The wavelength of sound waves in hydrogen gas corresponding to the lower limit of audibility is ( speed of sound in hydrogen gas is about 1350 m/s) .

Options

A. 60 m
B. 67.5 m
C. 100 m
D. 500 m

Answer

To find the wavelength of sound waves in hydrogen gas corresponding to the lower limit of audibility, we can use the formula that relates the speed of sound (v), frequency (f), and wavelength (λ):

\[ \lambda = \frac{v}{f} \]

### Step-by-Step Solution:

1. **Identify the given values**:
- Speed of sound in hydrogen gas, \( v = 1350 \, \text{m/s} \)
- Lower limit of audibility (frequency), \( f = 20 \, \text{Hz} \)

2. **Substitute the values into the wavelength formula**:
\[ \lambda = \frac{1350 \, \text{m/s}}{20 \, \text{Hz}} \]

3. **Perform the calculation**:
\[ \lambda = \frac{1350}{20} = 67.5 \, \text{m} \]

4. **Conclusion**:
The wavelength of sound waves in hydrogen gas corresponding to the lower limit of audibility is \( 67.5 \, \text{m} \).

### Final Answer:
The wavelength of sound waves in hydrogen gas corresponding to the lower limit of audibility is **67.5 meters**.

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