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A wave is represented by x=4 cos (8t-(y)...

A wave is represented by `x=4 cos (8t-(y)/(2))` , wher x and y are in metre and t in second. The frenqency of the wave ` ("in" s^(-1) ) ` is

A

`(4)/(pi) `

B

`(8)/(pi) `

C

`(2)/(pi) `

D

`(pi)/(4) `

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The correct Answer is:
To find the frequency of the wave represented by the equation \( x = 4 \cos(8t - \frac{y}{2}) \), we can follow these steps: ### Step 1: Identify the angular frequency (\( \omega \)) The given wave equation can be compared to the standard form of a wave equation, which is: \[ x = A \cos(\omega t - k y) \] where: - \( A \) is the amplitude, - \( \omega \) is the angular frequency, - \( k \) is the wave number. From the given equation \( x = 4 \cos(8t - \frac{y}{2}) \), we can identify that: - The angular frequency \( \omega = 8 \) (the coefficient of \( t \)). ### Step 2: Relate angular frequency to frequency The relationship between angular frequency (\( \omega \)) and frequency (\( f \)) is given by: \[ \omega = 2\pi f \] ### Step 3: Solve for frequency (\( f \)) We can rearrange the equation to solve for frequency: \[ f = \frac{\omega}{2\pi} \] Substituting the value of \( \omega \): \[ f = \frac{8}{2\pi} \] ### Step 4: Simplify the expression Now, we can simplify the expression: \[ f = \frac{8}{2\pi} = \frac{4}{\pi} \] ### Final Answer Thus, the frequency of the wave is: \[ f = \frac{4}{\pi} \, \text{s}^{-1} \] ---
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