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If tangents PA and PB from a point P to a circle with centre O are inclined to each other at angle of `80^@`, then `/_P O A` is equal to

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To solve the problem step by step, we will analyze the given information and apply the properties of tangents and triangles. ### Step 1: Understand the Problem We have a circle with center O, and two tangents PA and PB drawn from point P to the circle. The angle between these tangents, ∠BPA, is given as 80 degrees. We need to find the angle ∠POA. ### Step 2: Identify Relevant Properties Recall that the radius of a circle is perpendicular to the tangent at the point of contact. Therefore: - OA is perpendicular to AP, which means ∠OAP = 90 degrees. ...
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If PA and PB are tangents drawn from an external point P to a circle with centre O such that angle APB = 70^@ , then angle OAB is equal to: यदि PA और PB एक बाहरी बिंदु P से केंद्र O के साथ एक वृत्त में खींची गई स्पर्श रेखाएँ हैं जैसे कि angle APB = 70^@ तो angle OAB बराबर है:

PA and PB are two tangents from a point P outside a circle with centre O. If A and B are points on the circle such that angle APB= 80^@ , then angle OAB is equal to: PA और PB केंद्र O वाले वृत्त के बाहर स्थित बिंदु P से निकली दो स्पर्श रेखाएं हैं | यदि A और B वृत्त पर स्थित ऐसे दो बिंदु हैं कि angle APB= 80^@ है, तो angle OAB का मान क्या होगा ?

PA and PB are two tangents from a point P outside a circle with centre O. If A and B are points on the circle such that angle APB= 142^@ , then angle OAB is equal to: PA और PB केंद्र O वाले वृत्त के बाहर स्थित बिंदु P से निकली दो स्पर्श रेखाएं हैं | यदि A और B वृत्त पर स्थित ऐसे दो बिंदु हैं कि angle APB= 142^@ है, तो angle OAB का मान ज्ञात करे