Phosphorous pentachloride dissociates as follows (in a closed reaction vessel):
`PCI_(5)(g)hArrPCI_(3)(g)+CI_(2)(g)`
If the total pressure at equilibrium on the reaction mixture is P and the degree of dissociation of `PCI_(5)` is x, the partial pressure of `PCI_(3)` will be

Options

A. `((x)/(x+1))P`
B. `((2x)/(1-x))P`
C. `((x)/(x+1))P`
D. `((x)/(1-x))P`

Answer

A

Explanation

Given: `PCI_(5)(g)hArrPCI_(3)(g)+CI_(2)(g)`
`{:(t=0,1,0,0),(t_(eq),1-x,x,x):}`
Total number of moles`=1-x+x+x=1+x`
Thus partial pressure of `PCI_(3)=((x)/(1+x))P`.