The equilibrium constant for the given reaction:
`SO_(3(g))hArrSO_(2(g))+1//2O_(2(g))`, `(K_(c)=4.9xx10^(-2))`
The value of `K_(c)` for the reaction:
`2SO_(2(g))+O_(2(g))hArr2SO_(3(g))`, will be :

Options

A. `416`
B. `2.40xx10^(-3)`
C. `9.8xx10^(-2)`
D. `4.9xx10^(-2)`

Answer

B

Explanation

`SO_(3)(g)hArrSO_(2)(g)+(1)/(2)O_(2)(g)`
`([SO_(2)][O_(2)]^(1//2))/([SO_(3)])=K_(C)=4.9xx10^(-2)` ....(i)
`SO_(3)(g)+1//25 O_(2)(g)hArrSO_(3)(g) ......(ii)
([SO_(3)])/([SO_(2)]^(2)[O_(2)]^(1//2))=K'_(C)=(1)/(4.9xx10^(-2))"For"2SO_(2)(g)+O_(2)9(g)hArr2SO_(3)(g)`
`([SO_(3)]^(2))/([SO_(2)]^(2)[O_(2)](1//2))=K_(c^(2))=(1)/(4.9xx4.9xx10^(-10))=(10000)/(24.01)=416.49`