Ina `0.25` litre dissociation of 4 moles of NO takes place. If its degree of dissociation is `10%`. The value of `K_(p)` for reaction `2NO hArrN_(2) + O_(2)` is:

Options

A. `(1)/((18)^(2))`
B. `(1)/((8)^(2))`
C. `(1)/(16)`
D. `(1)/(32)`

Answer

A

Explanation

`{:(,2NO,hArr,N_(2),+,O_(2),alpha=10%),(t=0,4-.4,,.2,,.2,),(,3.6,,0.2,,0.2,):}`
`Deltan=0`,
`thereforeK_(p)=K_(c), K_(c)=((.2//V)^(2))/((3.6//V)^(2))=(4)/(36xx36)`