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For the given reaction at constant press...

For the given reaction at constant pressure,
`{:(,nA(g)hArr,A_n(g)),("Initial moles",1,0),("Final moles",1-alpha,alpha/n):}`
Then the correct relation between initial density `(d_i)` and final density `(d_f)` of the system is :

A

`[(n-1)/(n)][(d_(f)-d_(i))/(d_(f))]=alpha`

B

`(n)/(n-1)([d_(f)-d_(i)])/(d_(f))=alpha`

C

`[(n-1)/(n)][(d_(i)-d_(f))/(d_(i))]=alpha`

D

`(1)/((n-1))[(d_(i)-d_(f))/(d_(i))]=alpha`

Text Solution

Verified by Experts

The correct Answer is:
B
Total moles at equilibrium `=1-alpha+alpha//n=1+[(1)/(n)-1]alpha`
So using `(d_(i))/(d_(f))=1+[(1)/(n)-1]alpha`
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