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At room temperature, the equilibrium con...

At room temperature, the equilibrium constant for the reaction P + Q `hArr` R + S was calculated to be `4.32` . At `425^(@)C` the equilibrium constant became `1.24xx10^(-2)` . This indicates that the reaction

A

is exothermic

B

is endothermic

C

is difficult to predict

D

no relation between `DeltaH "and" K`

Text Solution

Verified by Experts

The correct Answer is:
A
At room temperature, `K=4.32`
and at `425^(@)C`, equilibrium constant become `1.24xx10^(-4)` i.e. it is decreases with increase in temperature. So, it is exothermic reaction.
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RESONANCE-CHEMICAL EQUILIBRIUM-Advanced Level Problems (Part-1)
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  18. For the reaction: PCl(5)(g)hArrPCl(3)(g)+Cl(2)(g) The forward reacti...

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  19. Find out InK(eq) for the formation of NO(2) from NO and O(2) at 298 K ...

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