For the reaction, `2Cl(g) rarr Cl_2(g)`, the correct option is:

Options

A. `triangle_rHgt0 and triangle_rSgt0`
B. `triangle_rHgt0 and triangle_rSlt0`
C. `triangle_rHlt0 and triangle_rSgt0`
D. `triangle_rHlt0 and triangle_rSlt0`

Answer

To solve the question regarding the reaction \(2Cl(g) \rightarrow Cl_2(g)\), we need to analyze the changes in enthalpy (\(\Delta H\)) and entropy (\(\Delta S\)) for the reaction.

### Step-by-Step Solution:

1. **Identify the Reaction Type**:
The reaction involves the combination of two chlorine atoms (Cl) to form a diatomic chlorine molecule (Cl2). This is a synthesis reaction.

2. **Determine \(\Delta H\)**:
- This reaction is exothermic because it involves the formation of a bond between two chlorine atoms to form Cl2.
- In exothermic reactions, energy is released, which means that the enthalpy change (\(\Delta H\)) is negative.
- Therefore, we conclude that \(\Delta H < 0\).

3. **Determine \(\Delta S\)**:
- Entropy (\(S\)) is a measure of randomness or disorder in a system.
- In this reaction, we start with 2 moles of gaseous chlorine atoms (2Cl) and end with 1 mole of diatomic chlorine (Cl2).
- Since the number of gas molecules decreases from 2 to 1, the randomness or disorder of the system decreases.
- Consequently, the entropy change (\(\Delta S\)) is negative.
- Therefore, we conclude that \(\Delta S < 0\).

4. **Summarize the Results**:
- We have established that \(\Delta H < 0\) and \(\Delta S < 0\).
- The correct option that matches both conditions is option 4.

### Final Answer:
The correct option is **4**, where both \(\Delta H\) and \(\Delta S\) are less than zero.