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C(6)H(5)N(2)Cl overset(SnCl(2)//HCl) (A)...

`C_(6)H_(5)N_(2)Cl overset(SnCl_(2)//HCl) (A) to overset(C_(6)H_(5)CHO)to(B)`
The product (B) in the above sequence of reaction is

A

`C_(6)H_(5)-N=N-C_(6)H_(5)`

B

`C_(6)H_(5)-N=CH-C_(6)H_(5)`

C

`C_(6)H_(5)-NH-N=CH-C_(6)H_(5)`

D

Text Solution

Verified by Experts

The correct Answer is:
C
Reduction of benzene diazonium chloride with `SnCl_(2)` and HCl gives phenyl hydrazine which reacts with benzaldeyde to form phenyl hydrazone.
`C_(6)H_(5)N_(2)Cl overset(SnCl_(2)//HCl)to(C_(6)H_(5)-NH-NH_(2)overset(C_(6)H_(5)CHO)to (C_(6)H_(5)-NH-N=CH-C-(6)H_(5)`
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