Identify (A),(B) and (C). Also explain colour difference between `MCl_(4)` and (B).

Explanation

(A) is `TiCl_(4)` as it has no unparied electron and is liquid at room temperature on account of covalent character because of high polarising power of `Ti^(+4).TiCl_(4)` being covalent gets hydrolysed forming `TiO_(2)(H_(2)O)_(2) and HCl`
(B) which fumes in air.
In `[Ti(H_(2)O)_(6)]Cl_(3)` complex Ti(III) has one unpaired electron `(3d^(1))` which gives violet/purple colour due to d-d transition.
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