Cuprous chloride can be prepared:

Options

A. by passing `SO_(2)` through the solution containing `CuSO_(4) and NaCl`
B. by heating excess of copper with concentrated HCl in presence of a little `KClO_(3)`
C. by boiling copper sulphate solution with excess of copper turnings in presence of hydrochloric acid.
D. by dissolving cupric oxide or coper carbonate in concentrated HCl.

Answer

A, B, C

Explanation

(A) `2CuSO_(4)+2NaCl+2H_(2)O+SO_(2)toCu_(2)Cl_(2)+Na_(2)SO_(4)+2H_(2)SO_(4)`
(B) `Cu+HCl+[O]toCuCl_(2)+H_(2)O,CuCl_(2)+CutoCu_(2)Cl_(2)`
(C) `CuSO_(4)+2HCl" "CuCl_(2)+H_(2)SO,CuCl_(2)+CutoCu_(2)Cl_(2)`
(D) `CuO+2HCl to CuCl_(2)+H_(2)O,CuCl_(2)` is not formed.