During estimation of nitrogen present in an organic compound by Kjeldahl’s method, the ammonia evolved from 0.5 g of the compound in Kjeldahl’s estimation of nitrogen, neutralized 10 mL of 1 M `H_(2)SO_(4)`. Find out the percentage of nitrogen in the compound.

Explanation

Volume of 1 M `H_(2)SO_(4)` used by `NH_(3)` =10 ml ,
Milliomoles of `H_(2)SO_(4)` used =10 x 1 =10. m . Moles
Millimoles of `NH_(3)` produced =2 x millimoles of `H_(2)SO_(4)`
`=2xx10 =20`
(2 mol of `NH_(3)` neutralise 1 mol of `H_(2)SO_(4)`)
Mass of `NH_(3)` formed =Moles of `NH_(3)` x molar mass =`20xx10^(-3) xx17 g`
Mass of N =`(20xx10^(-3)xx17xx14)/17 =0.28 g `
% of N =`(0.28xx100)/0.5 =56.0 % `