In the fcc arrangement of `A` and `B` atoms whose `A` atoms are at corners of the unit cell and `B` are at the face centres one of the `A` atom is missing from one corner in each unit cell. What is the simplest formula of the compound?

Options

A. `A_(7)B_(3)`
B. `AB_(3)`
C. `A_(7)B_(24)`
D. `A_(2)B_(3)`

Answer

C

Explanation

`A = 7 xx (1)/(8) = (1)/(8) , B = 6 xx (1)/(2) = 3`
Formula `= A_(7//8) B_(3) " or " A_(7)B_(24)`