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The distance between adjacent, oppositel...

The distance between adjacent, oppositely charged ions is rubidium chloride is `3.285Å`, in potassium chloride is `3.139Å` in sodium bromide is` 2.981Å`. And in potassium bromide is `3.293Å`. The distance between adjacent oppositely charged ions in rubidium bromide is:

A

`3.147 Å`

B

`3.385Å`

C

`3.393 Å`

D

`3.439Å`

Text Solution

Verified by Experts

The correct Answer is:
D
`(r_(Rb^(+)) + r_(Cl^(-))) + (r_(K^(+)) + r_(Br)) - (r_(K^(+)) + r_(Cl)) = (r_(Rb^(+)) + r_(Br))`
`3.285 + 3.293 - 3.139 = 3.439`
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