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Tangents are drawn from the origin to the curve `y = sin x`. Prove that their points of contact lie on the curve `x^(2) y^(2) = (x^(2) - y^(2))`

A

`x-y =xy`

B

`x+y =xy`

C

`x^(2) -y^(2) =x^(2)y^(2)`

D

`x^(2)+y^(2)=x^(2)y^(2)`

Text Solution

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The correct Answer is:
C
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