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If int(cos4x+1)/(cotx-tanx)dx=kcos4x+c, ...

If `int(cos4x+1)/(cotx-tanx)dx=kcos4x+c`, then k= (A) `-1/4` (B) `-1/2` (C) `-1/8` (D) none of these

A

`A=-1//4` and B may have any value

B

A`=-1//8` and B may have any value

C

`A=-1/2` and `B=-1//4`

D

`A=B=1/2`

Text Solution

Verified by Experts

The correct Answer is:
B
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