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The value of int(sinx.cosx.cos2x.cos4x.c...

The value of `int(sinx.cosx.cos2x.cos4x.cos8x.cos16x)`dx is equal to

A

`(sin16x)/(1024) + C`

B

`-(cos32x)/(1024)+C`

C

`(cos32x)/(1096)+C`

D

`-(cos32x)/(1096)+C`

Text Solution

Verified by Experts

The correct Answer is:
b
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Knowledge Check

  • intsinx.cosx.cos2x.cos4x.cos8x.cos16xdx is equal to

    A
    `(sin16x)/1024+c`
    B
    `-(cos32x)/1024+c`
    C
    `(cos32x)/1096+c`
    D
    `-(cos32x)/1096+c`

  • int cos 2x.cos 4x. Cos 6x dx is equal to

    A
    `(sin12x)/(12)+(sin 8x)/(4)+(sin 4x)/(2)+C`
    B
    `(1)/(4)[(sin12x)/(12)+sin 8x)/(4)+(sin 4x)/(2)]+C`
    C
    `(1)/(4)[sin12x)/(12)+(sin 8x)/(8)+(sin 4x)/(4)]+C`
    D
    None of these

  • If f(x)=cosx.cos2x.cos4x.cos8x.cos16x , then f'(pi)/(4) is equal to

    A
    `sqrt2`
    B
    `(1)/(sqrt2)`
    C
    1
    D
    `(sqrt3)/(2)`

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