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If I(n)=int(sinx+cosx)^(n)dx, snd I(n)=1...

If `I_(n)=int(sinx+cosx)^(n)`dx, snd `I_(n)=1/n(sinx+cosx)^(n-1)(sinx-cosx)+(2k)/(n) I_(n-2)` then k=

A

(n+1)

B

`(n-1)`

C

`(2n+1)`

D

`(2n-1)`

Text Solution

Verified by Experts

The correct Answer is:
b
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