A capacitor of capacitance `C_(0)` is charged to a voltage `V_(0)` and then isolated. An uncharged capacitor C is then charged from `C_(0)` , discharged and charged again , the process is repeated n times. Due to this, potential of the `C_(0)` is decreased to V, then value of C is :

Options

A. `C_(0)[V_(0)//V]^(1//n)`
B. `C_(0)[(V_(0)//V)^(1//n)-1]`
C. `C_(0)[(V_(0)//V)-1]`
D. `C_(0)[V//V_(0)^(n)+1]`

Answer

B