The capacitance of a parallel plate condenser is `C_(0)` If a dielectric of relative permittivity `epsilon_(r)` and thickness equal to one fourth the plate separation is placed between the plates, then its capacity becomes C. The value of `(C)/(C_(0))` will be -

Options

A. `(5 epsilon_(r))/(4 epsilon_(r)+1)`
B. `(4 epsilon_(r))/(3 epsilon_(r)+1)`
C. `(3 epsilon_(r))/(2 epsilon_(r)+1)`
D. `(2epsilon_(r))/(epsilon_(r)+1)`

Answer

B