1 meter long metallic wire is broken in...

`1` meter long metallic wire is broken into two unequal parts `P and Q. P` part of the wire in uniformly extended into another wire `R`. Length of `R` is twice the length of `P` and the resistance of `R` is equal to that of `Q`. Find the ratio of the resistance `P` and `R` and also the ratio of the length `P and Q`

Text Solution

Verified by Experts

The correct Answer is:

Topper's Solved these Questions

CURRENT ELECTRICITY
RESONANCE|Exercise Exercise-2 (Part-3)|22 Videos
CURRENT ELECTRICITY
RESONANCE|Exercise Exercise-2 (Part-4)|12 Videos
CURRENT ELECTRICITY
RESONANCE|Exercise Exercise-2 (Part-1)|25 Videos
COMMUNICATION SYSTEMS
RESONANCE|Exercise Exercise 3|13 Videos
DAILY PRACTICE PROBLEM
RESONANCE|Exercise DPP.No.71|1 Videos

Similar Questions

Explore conceptually related problems

One metre long metallic wire is broken into two unequal parts P and Q. The part P is uniformly extended into another wire R. Find the ratio of the resistances of P and R and also the ratio of the lengths P and Q.

In comparing the resistance of two cells P and Q with a sides wire bridge, a balance point is obtained when the sliding contact is 30 cm from the zero end of the wire. The resistances P and Q are interchanged and the balance is obtained at 120 cm from the same emf. Find the ratio of the resistance P and Q and the length of the bridge wire

P,Q and R are three partners in a business. If Ps capital is equal to twice the capital of Q and Qs capital in three times the capital of R, find the ratio of the capitals of P,Q and R.

A given piece of wire of length l and radius r and resistance R is stretched uniformly to wire of radius (r)/(2) .Its new resistance is:

{(p wedge (p to q)) wedge (q to r)} to r is equal to

With resistances P and Q in the left and right gaps of a metre bridge respectively, the null point divides the wire in the ratio 1 : 2 . If P and Q are increased by 20 Omega each, the null point divides the wire in the ratio 3 : 4, then the resistances P and Q are given as :

A wire made of material A has resistance R_1 another wire made of material B having P time the length and q times the radius of first wire has resistance R_2 . If resistivity of B is r times that of A, then calculate R_2//R_1 .

RESONANCE-CURRENT ELECTRICITY-Exercise-2 (Part-2)

The current density in a cylindrical conductor of radius R varies acco...
Text Solution
|
1 meter long metallic wire is broken into two unequal parts P and Q. ...
Text Solution
|
In the figur shown, the thermal power generated in 'Y' is maximum when...
Text Solution
|
A series parallel combination battery consisting of a large number N ...
Text Solution
|
The internal resistance of an accumulator battery of emf 6V is 10(Omeg...
Text Solution
|
A hemispherical network of radius a is made by using a conducting wire...
Text Solution
|
Find the resistance in ohm of a wire frame shaped as a cube (figure) w...
Text Solution
|
The figure is made of a uniform wire and represnts a regular five poin...
Text Solution
|
In the circuit shown in fig. E(1)=3" volt",E(2)=2" volt",E(3)=1" vole ...
Text Solution
|
The resistance of each resisor in the circuit diagram shown in figure ...
Text Solution
|
In the circuit shown in figure 16, E, F, G and H are cells of emf 2...
Text Solution
|
If the galvanometer in the circuit of figure reads zero, calculate the...
Text Solution
|
Shown an arrangement to measure the emf (epsilon)and internal resistan...
Text Solution
|
In the circuit shown, reading of the voltmeter connected across 400 Om...
Text Solution
|
In the given circuit the ammeter A(1)" and "A(2) are ideal and the amm...
Text Solution
|
Two resistors, 400 Omega, " and "800 Omega are connected in series wit...
Text Solution
|