Figure shows a long wire having uniform charge density `lambda` as shown in figure. Calculate electric field intensity at point P.

Explanation

`theta_(1)=90^(º)` and `theta_(2)=360^(º)-37^(º)` So

`E_(x)=(K lambda)/(r) [sin theta_(1)+sin theta_(2)], E_(y)=(K lambda)/(r) [cos theta_(2)- cos theta_(1)]`