Two charges, each of `5 mu C` but opposite in sign, are placed 4 cm apart. Calculate the electric field intensity of a point that is a distance 4 cm from the mid point on the axial line of the dipole.

Explanation

To solve the problem of calculating the electric field intensity at a point that is a distance of 4 cm from the midpoint on the axial line of a dipole formed by two charges of equal magnitude but opposite sign, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Charges and Their Positions:**
- Let the two charges be \( q_1 = +5 \, \mu C = 5 \times 10^{-6} \, C \) and \( q_2 = -5 \, \mu C = -5 \times 10^{-6} \, C \).
- The distance between the two charges is \( d = 4 \, cm = 0.04 \, m \).
- The midpoint between the charges is at a distance of \( 2 \, cm = 0.02 \, m \) from each charge.
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