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A short dipole is placed on the axis of ...

A short dipole is placed on the axis of a uniformly charged ring (total charge -Q, radius R) at a distance `R/sqrt(2)` from centre of ring as shown in figure. Find the Force on the dipole due to that ring

Text Solution

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`:' F=P ((dE)/(dx))`
`:. F=P d/(dx) ((KQx)/((R^(2)+x^(2))^(3//2))), ("at "x=R/sqrt(2))`
Solving we get, `F=0`
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