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A uniform electric field E=91xx10^(-6) V...

A uniform electric field `E=91xx10^(-6) V//m` is created between two parallel, charged plates as shown in figure. An electron enters the field symmetrically between the plates with a speed `v_(0)=4xx10^(3) m//s`. The length of each plates is `l=1m`. Find the angle of deviation of the path of the electron as it comes out of the field. (Mass of the electron is `m=9.1xx10^(-31) kg` and its charge is `e=-1.6xx10^(-19) C`).

Text Solution

Verified by Experts

The correct Answer is:
The electron deviates by an angle
`theta="tan"^(-1) (eEl)/(mv_(0)^(2))` (from x-axis)`=45^(º)`
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